x^2+17x+52=0.

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Solution for x^2+17x+52=0. equation: 



x^2+17x+52=0.

a = 1; b = 17; c = +52;
Δ = b2-4ac
Δ = 172-4·1·52
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-9}{2*1}=\frac{-26}{2}
=-13
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+9}{2*1}=\frac{-8}{2}
=-4
$

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